Solve by factoring: 2x^2-5x-3=0?
(2x-3)(x-1)
2x^2-6x+x-3 = 0 2x(x-3)+1(x-3) = 0 (2x+1)(x-3) = 0 x=-1/2,x=3
which one is correct?
aroub can u explain this ?
lol idk!
yes sure!
thanks
ok , ill explain my answer
but what do u want to know exactly?
how you got the factors
ok , there are many different ways to do it!!!! but ill tell u my way
ok ill use ur example 2x^2-5x-3 ok u look at 3 and u say to urself what times what gives u 3, the only numbers u have is 3*1, then u look at 2 what times what gives u 2x^2 its 2x and x so u put them in brackets ex. (2x )(x ) then u look at the signs here in the example u have negative and negative the first sign u see it u put it in the first bracket (2x- )(x ) the second/ lol never mind ill write it on a paper and then put it in here for u to see it okay can u wait just another 5 min please i really want to help u !!
thanks again if u dont mind please post it i ll never forget your help aroub thanks a 100 times
anytime my freind u seem like a very good , nice , kind person! ill sure like to help these kind of people!!!
but i want to post other example for u to understand more... okay?
oh and tell me if u can see the numbers ... lol
when u r getting time please post it,i am going once again thanks
okay inshallah we u come back u will see it posted okay , byyeee!!! ::) :)
when**
inshallah tomorow
wait can u wait 2 more min pleasee
okay :)
LOL INSHALLAH TOMORROW TOMORROW bec. the numbers are not really showing ill fix it and post it on here
SORRYY!! :( :(
oh sry but r u muslim??
my name is jumaliya can u guess
then u are!?1!!!!
yea
i know jumana but not jumaliya
oh great! bec. i keep saying inshallah not realizing ALHAMDILLAH u are!!! :D
bye arounb thank you very much for all the helps
OKAY BYE/ ANYTIME XX
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