Question

can someone help me solve this?
http://mathway.com/math_image.aspx?p=SMB02FSMB035xSMB02ESMB032SMB02eSMB03+6x-27SMB1028xSMB02ESMB033SMB02eSMB03+24xSMB02ESMB032SMB02eSMB03SMB02fSMB03*SMB02FSMB0321xSMB02ESMB032SMB02eSMB03+39x+18SMB1015xSMB02ESMB032SMB02eSMB03-12x-27SMB02fSMB03?p=217?p=42

Answer 1

\[\dfrac{(5x^2+6x-27)(21x^2+39x+18)}{(28x^3+24x^2)(15x^2-12x-27)}=\dfrac{(5x^2+6x-27)(7x^2+13x+6)}{4x^2(7x+6)(5x^2-4x-9)}=\]
=\[\dfrac{(5x-9)(x+3)(7x+6)(x+1)}{4x^2(7x+6)(5x-9)}=\dfrac{(x+3)(x+1)}{4x^2} , x \neq -6/7,9/5\]

Answer 2

can you check the work i did on problem number two to see what i did wrong

Answer 3

in the third line there is a mistake $$ 5x^2+6x-27=x(5x-9)+3(5x-9)=(5x-9)(x+3)$$

Answer 4

oh i see it now thank you so much

Answer 5

can you also check number one cause i think i got that one wrong to