Question

The equation of the line l is 5y-4x=10 write the standard form of the equation of the line that fits each description. A)parallel to l and passes through the pt at(-15,9).
B) perpendicular to l n passes through the pt at (-15,8)

Answer 1

Putting line 1 in slope intercept from y=(4/5)x+2 The slope is 4/5

A) A parallel line will have same slope so the equation for this line will use:
4/5=(y-9)/(x+15) cross multiplying getting
4x+60=5y-45 rearranging and combining getting:
y=(4/5)x+21 y intercept form equation for the parallel line.

B) Perpendicular line will have the negative reciprocal of the slope for line 1.
Slope for perpendicular will be: -5/4
Equation for the perpendicular line will be:

-(5/4)=(y-8)/(x+15) Cross multiplying getting:

-5x-75=4y-32
4y-32=-5x-75
4y=-5x-75+32
y=-(5/4)x-43 which is the slope intercept form equation of the perpendicular line.