Question

can anybody help me with this matrix?

Answer 1

i need help with number 8

Answer 2

do row times column basically..

Answer 3

So those matrices are..
2x3 and 3x2

Answer 4

The result will be 2x2, so the first entry is:
4*-4 + -7*6 + 0*1

Answer 5

so the matrix so far looks like:
[ -58 x
x x

Answer 6

Keep repeating for every entry..
so the entry in row 1 column 2 would be row 1 times column 2

Answer 7

\[\left[\begin{matrix}(4)(-4)+(-7)(6)+(0)(1) & (4)(2)+(-7)(0)+(0)(-9) \\ (3)(-4)+(5)(6)+(-1)(1) & (3)(2)+(5)(0)+(-1)(-9)\end{matrix}\right]\]

Answer 8

nice guru!

Answer 9

ok thnk u i can do it from here =)

Answer 10

lol i hope so

Answer 11

so what do i do with all the zeros?

Answer 12

Multiply them as usual

Answer 13

i.e., 0*1=0 -7*0=0 .. is that what you mean?

Answer 14

yes bt i solved it