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Find the points of inflection; 2csc(3x/2) (0,2pi)..describe the concavity
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points of infliction come from the second derivative, do you have the second derivative
9/4(cos(3x)+3)csc^3(3x/2)
okay, now you must determine where or at what values this derivative is zero
omg i only have 2 mins left!!!omg omg do u mind just giving me th points.....its a timed homework exam!:(
:'(
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no inflection points
how would u desribe the concavity
concave up (0,2pi/3) (4pi/3,2pi)
concave down (2pi.3,4pi.3)
concave down (2pi/3,4pi/3)
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its the same:S?
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