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Find the coordinates of the points on a line 3x-4y=1 which are 5 units away from 3,2 which is also on the line
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call the point (a,b) then you know \[(a-3)^2+(b-2)^2=25\] and \[3a-4b=1\] solve these simultaneously get \[(-1,-1),(7,5)\]
5 is the hypoteneuse of a 3,4,5 triangle (slope is 3/4) so the points are (3,2) +- (4,3)
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