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In how many ways can 8 people each have different birthdays? Assume that there are 365 days in a year.
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365*364*363*362*361*360*359*358 or \[\frac{365!}{358!}\]
how did you know how to do that?
are you sure 365 -8 =357 ?
sorry should have been \[\frac{365!}{357!}\]
why 357?
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first person can have birthday any day of the year, 365 days second person , every day except ^ that one day 364 ................ ............... .................
gotchaaaa
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