Question

Hey imran I finally figured out how to do that program assignment, give me about ten minutes I will post the solution here.

Answer 1

I mean I will post the program and have you guys test it.

Answer 2

gj, I figure my own way but that used a little bit more than mere if else

Answer 3

LOL I am using 24 if-elses haha

Answer 4

11 more left..

Answer 5

My idea was finding min of a,b,c,d and assigning it to a
finding min of b,c,d and assigning it to b
finding min of c,d and assigning it to c

Answer 6

hmm nice... How woud you do that? I thought of that, but i just brushed it off saying whatever..

Answer 7

Using some nested if statement and a function.No loops, array needed

Answer 8

ohh 7 more left.. arghhh

Answer 9

I am going to be taking assembly language this fall which is supposed to be fun

Answer 10

3 to go!!! lol I am minoring in programming now.. i decided it is sort of fun.. easier than math at least

Answer 11

Mathematical Computer Science related to math since it is problem solving using programming

Answer 12

Okay done. here's the program.

Answer 13

First test passed

Answer 14

1234 1243 1324 1342 1423 1432
2134 2143 2314 2342 2413 2431
3124 3142 3214 3241 3412 3421
4123 4132 4213 4231 4312 4321
Can you test all of these numbers?

Answer 15

Because the conditions are all dependant on the permutations

Answer 16

How does it handle repeat?

Answer 17

what do u mean repeat? I dunno...

Answer 18

1 3 4 1

Answer 19

oh snap it's not doing anything.. i should have done <=

Answer 20

hold on...

Answer 21

Okay fixed the bug, try again.. hold on let me reupload

Answer 22

here

Answer 23

That was quick

Answer 24

I think it is fool proof now

Answer 25

okay wanna see the source code?

Answer 26

yea, sure

Answer 27

lol I don't think you want to.. anyway hold on..

Answer 28

That was soo annoying to write, simple but annoying

Answer 29

I will try to simplify it

Answer 30

oh, changing to =< was your fix?

Answer 31

yea

Answer 32

very nice, long but very easy to follow

Answer 33

yea i googled all combinations of ABCD.. so I just used that

Answer 34

http://answers.yahoo.com/question/index?qid=20081005200021AAQs3Hr
Used that

Answer 35

In this case using brute force seems better than using tricks

Answer 36

yea.. oh wait.. i have to reject anything that is not an integer..

Answer 37

ah nevermind, professor's version is worse

Answer 38

when decimal is entered, it goes off

Answer 39

yea but the requirement says only integers

Answer 40

professor's version also fails

Answer 41

you can write that when accepting input

Answer 42

yea let me add that

Answer 43

I don't understand why you didn't do what I said. Or what imran said. Just 6 ifs

Answer 44

what do u mean? lol I just used the brute force method

Answer 45

So did I.

Answer 46

What I said in your last thread, or what imran said here:
"
My idea was finding min of a,b,c,d and assigning it to a
finding min of b,c,d and assigning it to b
finding min of c,d and assigning it to c
"

Answer 47

But my approach involve moving around value of a,b,c,d which is kind of annoying

Answer 48

only a little, and he probably is doing it anyway

Answer 49

No, he is just outputing a,b,c,d in different order

Answer 50

oh. still our method only has 6 ifs, not 24

Answer 51

power of copy/paste, lol

Answer 52

also if he used a function to swap the values its not too bad. c++ has references so changing the variables is easy

Answer 53

I tried function, but I don't know how global/local variable works in C++

Answer 54

void swap(int &a, int &b) { int tmp; tmp = a; a = b; b = tmp; }

Answer 55

then just:

swap(c,d) does the right thing

Answer 56

swap function? never heard of it..

Answer 57

#include <iostream>

using namespace std;

void swap(int &x,int &y)
{
int tmp;
tmp= y;
y= x;
x= tmp;
}

int main()
{
int a,b,c,d;
cout << "Please enter the 1st integer: " << endl;
cin >> a;
cout << "Please enter the 2nd integer: " << endl;
cin >> b;
cout << "Please enter the 3rd integer: " << endl;
cin >> c;
cout << "Please enter the 4th integer: " << endl;
cin >> d;


if (a>b) swap(a,b);
if (a>c) swap(a,c);
if (a>d) swap(a,d);
if (b>c) swap(b,c);
if (b>d) swap(b,d);
if (c>d) swap(c,d);

cout << "Sorted: " << a << " " << b << " " << c << " " << d << endl;


return 0;
}

Answer 58

If you haven't got to call by reference, this might be a bit mysterious.

Answer 59

Wow, nice looks soo good!! let me look up what swap does..