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solve the exponential equation (round to four decimal places) 3(7-11^5x-2)=10
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\[3(7-11^{5x-2})=10\]
divide by 3
\[7 - 11^{5x-2} = \frac{10}{3}\]
\[11^{5x -2} = 7 - \frac{10}{3} \]
Oh sorry take Log with Base 11
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x = 2 - log3 ----------- 5
oops
is it wrong ?
\[x = \frac{ 2 - \log_{11} 3}{5}\]
my answer was 0.8090 which is says isn't right
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