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find then inverse of h if h(x)=-8x/x-4. state the domain and range
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Ok
waht
\[\frac{-8x}{x -4} =h(x)\]
Lets take h(x) = y
-8x = y x - 4y
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8x + yx = 4y \[x = \frac{4y}{8 + y}\]
This is your Inverse \[h(x) = \frac{4x}{8 + x}\]
Now domain should real numbers except x = -8
(-inf,-8)U(-8,inf)?
As domain and (-inf,4)U(4,inf) as range?
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Yeah You can say that too
haha I just want to check with you on everything :D
sharks is right for domain and range too
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