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OpenStudy (anonymous):
if the sum of three consecutive integers is less than 120 ,what is the greatest possible value of the smallest of the three integers?
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OpenStudy (anonymous):
Set up an equation a+(a+1)+(a+2)=120
OpenStudy (anonymous):
3a=117
OpenStudy (anonymous):
a=39
OpenStudy (anonymous):
39+40+41=120
OpenStudy (anonymous):
So your answer will be 39
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