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Mathematics 20 Online
OpenStudy (anonymous):

if the sum of three consecutive integers is less than 120 ,what is the greatest possible value of the smallest of the three integers?

OpenStudy (anonymous):

Set up an equation a+(a+1)+(a+2)=120

OpenStudy (anonymous):

3a=117

OpenStudy (anonymous):

a=39

OpenStudy (anonymous):

39+40+41=120

OpenStudy (anonymous):

So your answer will be 39

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