Question

if A+B =225, prove that : cot A /1+cot A , Cot b/1+cot B =1/2

Answer 1

if:
\[A+B = 225\]
then:
\[\frac{\cot(A)}{1+\cot(A)}\]
\[\frac{\cot(B)}{1+\cot(B)}=\frac{1}{2}\]
?
what about the first fraction? what does it equal?

Answer 2

prove both are = to 1/2

Answer 3

Where did you get this prblem from? its not necessarily true. If i take A = 180, and B = 45 (in degrees), i get:
cot(180) = 0
cot(45) = 1
\[\frac{\cot(180)}{1+\cot(180)} = \frac{0}{1} = 0\]
\[\frac{\cot(45)}{1+\cot(45)} = \frac{1}{2} \]
Only one of them is equal to 1/2, not both.