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Computer Science 19 Online
OpenStudy (anonymous):

ALGORITM FOR TO CHECK PALINDROME OR NOT

OpenStudy (anonymous):

the main algo to check palindrome is inside the while loop :)

OpenStudy (anonymous):

#include<stdio.h> #include<conio.h> main() { int a[10],num,i=0,result=0,n; printf("Enter a number"); scanf("%d",&n); num=n; while(num!=0) { result=result*10; a[i]=num%10; num=num/10; result=result+a[i]; i++; } if(result==n) printf("Number is a palindrome"); else printf("Not a palindrome"); getch(); }

OpenStudy (anonymous):

def isPalindrome(word): if type(word) is not string: word=str(word) word=word.upper() if word==word[::-1]: return True else: return False Then, call isPalindrome for your word, isPalindrome("Racecar")=True

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