Question

#include #include main() { clrscr(); char a='y'; int num; while(a=='y') { printf("\nEnter a number\n"); scanf("%d",&num); printf("the square of %d is %d",num,num*num); printf("\nWant to enter another number y or n"); scanf("%c",&a); getch(); } getch(); } whats wrong in this.. its not going ahead even if i type y..

Answer 1

remove the getch inside the while loop

Answer 2

yes i will try and see now.. but how would that matter?

Answer 3

no.. its still the same... even if i remove getch it is happening just once.. den if i type y or n it is not going further..

Answer 4

let me check it wait

Answer 5

#include<stdio.h>
#include<conio.h>
main()
{

char a;

int num;
do
{
printf("\nEnter a number\n");
scanf("%d",&num);
printf("the square of %d is %d",num,num*num);
printf("\nWant to enter another number y or n");
a=getchar();

}
while(getchar()=='y') ;
getch();

}

Answer 6

when the scanf("%c",&a); statement was executed you typed y and hitted enter but ecuz of hitting enter a \n character was also inserted in a thats y the value of a became y and a \n which make the while loop false and nothing was coming again , sos to take one character as an input use getchar() method

Answer 7

use void main() or int main() & return 0; in the end ...... should complete these things..