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Mathematics 22 Online
OpenStudy (anonymous):

what is lx-3l> 2?

OpenStudy (anonymous):

when: x-3>2 or x-3<-2

OpenStudy (anonymous):

You need to solve for both -2 and 2 since you are taking the absolute value on the left: \[x-3>2\] \[x>5\] \[x-3>-2\] \[x>1\]

OpenStudy (anonymous):

@ Osirisis it should be x<1

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