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can someone help me out with this problem: x^(2/3) + x^(1/3) - 6 =0
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Im asked to find x
already found the answer
Consider x^1/3 = y ---- [1] it will form a quadratic equation as y^2 - y + 6 = 0 solve y and the put the value of y in [1]
sorry it will form a quadratic equation as y^2 + y 6 6 = 0
y^2 + y - 6 = 0
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Im rising every element in the equation to the third power, so x2 + x -216=0 Am I right?
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