Question

lets try this again i need help step by step for this equation square root of 4x plus 5 minus the square root of x minus one equals 3

Answer 1

\[\sqrt{4x + 5} - \sqrt{x - 1} = 3\]
\[\sqrt{4x + 5} = 3 + \sqrt{x - 1}\]
\[4x + 5 = ( 3 + \sqrt{x - 1} )^2\]
\[4x + 5 = 9 + 6\sqrt{x - 1} + x -1\]
\[4x + 5 = 8 + 6\sqrt{x - 1} + x \]
\[4x + 5 -x -8 = 6\sqrt{x - 1} \]
\[3x - 3 = 6\sqrt{x - 1} \]
\[ (3x - 3)^2 = (6)^2(x - 1) \]
\[ 9x^2 - 18x + 9 = (36)(x - 1) \]
\[ 9x^2 - 18x + 9 = 36x - 36 \]
\[ 9x^2 - 18x + 9 -36x + 36 = 0 \]
\[ 9x^2 - 54x + 45 = 0 \]
\[ (3x - 3)(3x - 15 ) = 0 \]
\[ 3x - 3 = 0 ; 3x - 15 = 0 \]

Answer 2

\[ 3x - 3 = 0 \]
\[ 3x = 3 \]
\[ x = 1 \]

Answer 3

\[ 3x - 15 = 0 \]
\[ 3x = 15 \]
\[ x = 5 \]

Answer 4

Is that okay??

Answer 5

hang on one sec

Answer 6

omg thank you so much i have been stguck on this prob for 2 days

Answer 7

What grade are you? And BTW, don't say OMG because you're putting the name of God in vain. (If that's what you ment my that abbreviation) :))

Answer 8

*meant

Answer 9

*by. LOL Typo.

Answer 10

math 100 and no its oh my goodness i dont use God in in in vain vocab only in postive speaking

Answer 11

and i know you r probably saying wow u r in only math 100 and u needed help but it has been 14 years since i have taken a math course thank you for your help

Answer 12

what's a math 100? LOL. There's no Math 100 here in the Philippines. XD

Answer 13

intermediate algrebra for college math befor calculus

Answer 14

Oh. College math. So, you're a college student?