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PLEASE HELP :) Find the lateral area for the regular pyramid. L. A. =
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LA = (1/2)*P*l P is the perimeter of the base P = 12+12+12 P = 36 l is the slant height l = sqrt(10^2 - (12/2)^2) l = sqrt(100 - 36) l = sqrt64 l =8 LA = 36*8/2 LA = 36*4 LA = 144 SQUARE UNITS
THANKS SO MUCH :)
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