What is the standard form equation of the line passing through (3, –2) with a slope of 3/5 ?
Answer
5x – 3y = 19
5x – 3y = –19
3x – 5y = –19
3x – 5y = 19

Question

What is the standard form equation of the line passing through (3, –2) with a slope of 3/5 ?
Answer   
 5x – 3y = 19 
   5x – 3y = –19 
   3x – 5y = –19 
   3x – 5y = 19

anonymous · Answer

rewrite in the form y = mx + c 
- m = slope and then find which fits the (3,-2)

aroub · Answer

y=mx+b , m=3/5 , (3,-2)
-2=3/5(3) +b
-2=9/5+b
-10/5-9/5 =b
-19/2=b
so the equation is y=3/5x-19/2

anonymous · Answer

wich changes to wich one?

aroub · Answer

oh okay , so 3x – 5y = –19

aroub · Answer

oh and i meant to write the y-intercept -19/5