Question

the perimeter of a rectangle is 210inches. the length exceeds the width by 61 inches. find the length and width

Answer 1

2l+2b=210
l-b=61
l=83
b=22

Answer 2

I agree with the above answer. Here is how I solved the problem:

Let w=width
Let l=length=w+61

P=2w+2l
P=2w+2(w+61)
210=2w+2w+122
210-122=2w+2w
88=4w
22=w

l=w+61=22+61=83

Therefore, the width=22 and the length=83