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OpenStudy (monty):
∫▒1/(2x^2+ 8).dx
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OpenStudy (anonymous):
= INT (1/2) 1/ (x^2 + 4) dx the reciprocal is a standard integral - u can check that out - i can't remember it to be honest - i thank its arctan x/2 but im not sure
OpenStudy (anonymous):
try wolframalpha.com
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