Question

∫1/(2x^2+ 8).dx

Answer 1

This is a standard integral (arctan)

Answer 2

As estudier noted:

\[\int\frac{1}{2x^2+8}dx=\frac{1}{8}\int\frac{1}{\frac{x^2}{4}+1}dx=\frac{1}{8}\int\frac{1}{\left(\frac{x}{2}\right)^2+1}dx=\cdots\]