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OpenStudy (anonymous):
how do i determine the value of the expression cos(sin^-1 1/2)
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OpenStudy (zarkon):
draw a right triangle ..or... cheat http://www.wolframalpha.com/input/?i=cos%28sin^-1+1%2F2%29&t=ietb01
OpenStudy (anonymous):
U need to learn all these standard trig ratios by heart... Sin pi/6 is 1/2 and cos pi/6 is sqrt3/2
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