Question

The perimeter of a rectangle is 76m. If the width were double and the length were increased by 17 m, the perimeter would be 140 m. What are the length and width of the rectangle?

Answer 1

HI ABC.

Answer 2

P = 2(a+b) = 76

Answer 3

let a be width and b be length

Answer 4

Actually nevermind let me use w for width and l for length

Answer 5

2(w+b)=76
2(2w+l+17) = 140

Answer 6

length=23m and width=15m

Answer 7

Solve the two equations

Answer 8

w+b = 38
2w + l + 17 = 70

Answer 9

2L + 2W = 76
Simplify divide by 2
L + W = 38
or
L = 38 - W
:
"If the width were doubled and the length were increased by 17m, the perimeter would be 120 m."
2(L+17) + 2(2W) = 140
2L + 34 + 4W = 140
2L + 4W = 140 - 34
2L + 4W = 106
Simplify divide by 2, subtract the 1st equation
L + 2W = 53
L + W = 38
-------------Subtraction eliminates L, find W
W = 15 is the width
then
L = 38 - 15
L = 23 is the length
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