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Mathematics 19 Online
OpenStudy (anonymous):

If sinθ > 0 and tanθ < 0 then: A. 180º < θ< 270º B. 90º <θ < 180º C. 0º <θ < 90 D. 270º <θ < 360º

OpenStudy (anonymous):

B

OpenStudy (anonymous):

thanks

OpenStudy (saifoo.khan):

B

jimthompson5910 (jim_thompson5910):

since tan=sin/cos and sine is positive but tan is negative, this must mean that cosine is negative. So theta is in quadrant II. So B is your answer.

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