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How big is the chance that when you grab 3 random numbers lower than 10.000, their added value is dividable by 100?
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Not so simple (unless I'm missing something). If u grab 3 numbers ending in 00 that's not too bad so u can do that separately. Else the units digits (a,b,c say) have to add so that the last digit is 0) and the tens digits have to do the same (possibly with a carryover..). I don't really want to work that out:-)
I guess its 720 posibilities... I not sure about it.
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