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show that the points (1,-1), (-1,-5) and (2,1) lies on a straight line. Use determinant. Prove by graphing. graphing is easy but what about determinant?
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i guess u show that the area of the triangle formed by 3 points is calculated using determinants
it looks smth like this 1 x1 y1 1 x2 y2 =2 * Area=0(here) 1 x3 y3
x1 y1 ....are the coordinates in the question. i hope you understood
If [x1 y1 1, x2 y2 1, x3 y3 1] = 0 -> colinear.
is it also the same in solving the concurrent line?
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yep u can say lines made by selecting any 2 points r concurrent, hence points are in 1 line.
by concurrent here i meant u get the same equation for the line both the times
thanks..
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