Question

Find the equation of the line tangent to the graph of f (x) = sqrt(x + 1) at the point (3,2).

Answer 1

which format? slope intercept of point slope form?

Answer 2

not that format is important; but rather:

the slope (m) = f'(3)

Answer 3

Either one is fine.

Answer 4

sqrt(x+1) derives to:

1/2sqrt(x+1) ; and i dont see any chain rule trickery so that should be good

Answer 5

f'(3) = 1/2sqrt(4) = 1/4 right?

Answer 6

y-Py = m(x-Px) ; where m=f'(3) and P(3,2)