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How do I solve y (as an integer or fraction)? sqrt y+2 -6= 4 (the sqrt only goes over y+2, just didnt know how to write that out on here) :)
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subtract 6 from both sides of the equation
sorry, add six :-)
then subtract 2 on both sides leaving you with sort y = 8
*sqrt y = 8
then square both sides of the equation => y = 64
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awesome!! =)
I'm out, good luck with the rest :-)
Thanks :)
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