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Solve: y = x2 + 8x + 9 x - y = -3
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is it y=x^2 + 8x +9 ?
It usually is
yea
transpose the variable y in the equation x-y=-3
put \[y=x+3\] in first equation to get \[x+3=x^2+8x+9\] hen solve the quadratic
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you solve \[x^2+7x+6=0\] \[(x+6)(x+1)=0\] \[x=-6,x=-1\]
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