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√5a + 3√125a^3
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Is the a^3 under the square root as well?
3 outside the sq root an small 3 above a so yes
\[\sqrt{5a}+3\sqrt{125x^3}\]?
correct
satellite73 yes
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oh ok then it is \[\sqrt{5a}+3\times 5a\times \sqrt{5a}\] \[\sqrt{5a}+15a\sqrt{5a}=(1+15a)\sqrt{5a})\]
satellite73 do i use the closed parenthese at the end behind the sq. rt.
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