Question

ok so I have it this far and I'm stuck... see below...

Answer 1

You didn't get very far :/

Answer 2

lol

Answer 3

\[\left(\begin{matrix}5 \\ 2x\end{matrix}\right)+\left(\begin{matrix}8 \\ x\end{matrix}\right)\]=1
\[2x \left(\begin{matrix}5 \\ 2x\end{matrix}\right)+\left(\begin{matrix}8 \\ x\end{matrix}\right)=2x \times1\]
\[2x \times \left(\begin{matrix}5 \\ 2x\end{matrix}\right)+2x\left(\begin{matrix}8 \\ x\end{matrix}\right)=2x \times1\]

Answer 4

I was typing it

Answer 5

?

Answer 6

Um.. hmm well I came up with 21/2x

Answer 7

oh yeah sorry I need to solve for x

Answer 8

are those suppose to be fractions?

Answer 9

how so?

Answer 10

yeah, I don't know how to do them on here

Answer 11

OHHHH I'm sorry! I didn't see the =1

Answer 12

frac{}{}

Answer 13

ok thanks I'll remember that

Answer 14

2x=21 or x=21/2 then

Answer 15

ok that's actually what I got just making sure, I thought I was missing something

Answer 16

\[\frac{5}{2x}+\frac{8}{x}=1\]
\[2x*(\frac{5}{2x}+\frac{8}{x}=1)\]
\[5+16=2x\]
right shark

Answer 17

Yes sir myininaya.. multiply it by 2x because it's the LCD

Answer 18

these binomials??

Answer 19

i guess i will let you get a away with calling me sir

Answer 20

hello sir

Answer 21

Thank you, maybe I just need to stop second guessing myself with this stuff

Answer 22

fractions
i already asked

Answer 23

Erm.. Sorry >.< Yes ma'am! haha

Answer 24

what i am supposed to read? thought this was a math site!

Answer 25

Can you guys help me with one more?

Answer 26

ok which one makes fractions?

Answer 27

\[\frac{x+5}{x-2}=\frac{x-2}{x+4}\]

Answer 28

cross multiply