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Simplify by removing factors of 1. y^2-1/1-y
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The numerator is difference of squares: (y-1)(y+1)/(1-y) Simplify from there
I get -1
But I think that is wrong
How did you get negative 1?
\[\frac{(y-1) (y+1)}{1-y} \]\[-\frac{(y-1) (y+1)}{-(1-y)} \]\[-\frac{(y-1) (y+1)}{(y-1)} \]\[-(y+1) \]
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