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find f '(x) from : f (x) = 3x (x ^ 3-1)
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12x^3-3 using product rule
f (x) = 3x (x ^ 3-1) =3x^4 -3x f'(x)=12x-3
mark 12x^3 dude
Or easy to understand is ... multiply it to get f9x0 = 3x^4-3x and then differentiate to get 12x-3. (Remember d/dx(x^n) = nx^(n-1)
ok... good job mark...
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