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(-x+2)/(x+7)<0 would be shown as (-inf,-7)U(2,inf) correct?
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yes right dude...
Thanks for checking!
\[\frac{x-2}{x+7} > 0 \] -7 2 -----------|---------------------------|---------------------- +++++++ ------------------------- + + + + + + + + + + + You did that right
yes right..... i also multiplied(x+7)^2 on both sides to make it simpler and then the graph
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