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OpenStudy (anonymous):
(-x+2)/(x+7)<0 would be shown as (-inf,-7)U(2,inf) correct?
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OpenStudy (akshay_budhkar):
yes right dude...
OpenStudy (anonymous):
Thanks for checking!
OpenStudy (anonymous):
\[\frac{x-2}{x+7} > 0 \] -7 2 -----------|---------------------------|---------------------- +++++++ ------------------------- + + + + + + + + + + + You did that right
OpenStudy (akshay_budhkar):
yes right..... i also multiplied(x+7)^2 on both sides to make it simpler and then the graph
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