The area of a rectangle is given by the expression 6x^2-13x-5
a) What is the length of the rectangle if its width is (2x+5)?
b) if x=9cm, find the length, width, and area of a rectangle
PLS HELP ME!!! SHOW YOUR SOLUTION write also A or B its Factoring Special Products Pls help me
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OpenStudy (anonymous):
You hate math Help!!
OpenStudy (anonymous):
I hate Miley Cyrus !! :P
OpenStudy (anonymous):
pls help me...
OpenStudy (anonymous):
but you hate math help lol I will just give me sometime
OpenStudy (anonymous):
pls just help
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OpenStudy (anonymous):
Okay \[A = 6x^2 -13x-5\]
Well I think your first option is insufficient so I will try b
OpenStudy (anonymous):
ishaan the maths superhero......;)
OpenStudy (anonymous):
When x=9
\[A = 6 \times 81 - 13 \times 9 -5\]
OpenStudy (anonymous):
LOL
OpenStudy (anonymous):
Now Solve it through Calculator
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OpenStudy (akshay_budhkar):
6x^2-13x-5 divided by 2x+5 wil give you the width
OpenStudy (anonymous):
ummm thats b? the answer? ok
OpenStudy (anonymous):
OK Akshay is right !!!
OpenStudy (anonymous):
a is not wrong ishaan...................
OpenStudy (anonymous):
A=6x^2−13x−5
When x=9
A=6×81−13×9−5
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OpenStudy (anonymous):
yeah Hash I didn't get that at first
OpenStudy (anonymous):
divide area by width to get length expression
OpenStudy (akshay_budhkar):
as area is length*width
OpenStudy (anonymous):
6x^2-13x-5 divided by 2x+5 wil give you the width
pls solve for me thanks
OpenStudy (anonymous):
Yeah Hash and Akshay are right thers is no need for superhero :D
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OpenStudy (akshay_budhkar):
why am i getting its not divisible??????
OpenStudy (anonymous):
pls solve this
6x^2-13x-5 divided by 2x+5 wil give you the width
OpenStudy (akshay_budhkar):
Hash786 ishaan??????? its not divisible u get a remainder
OpenStudy (anonymous):
it is a wrong quesstion.................there is a remainder
OpenStudy (anonymous):
which must not come particularly if A=LxB
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OpenStudy (akshay_budhkar):
i believe its wrong ihatemathhelp
OpenStudy (anonymous):
what is the length of the rectangle if its width is (2x+5)?
OpenStudy (anonymous):
can u check the area expression i hate math
OpenStudy (akshay_budhkar):
still the same!! wrong ques..
OpenStudy (anonymous):
i will scan the retricecan u still help me?
1min? i will scan
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OpenStudy (akshay_budhkar):
sure
OpenStudy (anonymous):
ok we can try to........
OpenStudy (anonymous):
w8
OpenStudy (anonymous):
Oh Lovely Akshay will do it and Hash too
OpenStudy (anonymous):
lol
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OpenStudy (akshay_budhkar):
ishaan is not interested he wants tough ques right?
OpenStudy (anonymous):
w8 its scanning
OpenStudy (anonymous):
Well the thing is i hate calculation ..and theres a lot in it
OpenStudy (anonymous):
Just get x.....
OpenStudy (anonymous):
help me :(
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OpenStudy (anonymous):
what do you mean?
can u help ,me can u solve it for me? pls...
OpenStudy (akshay_budhkar):
estudier the function is not divisible.....:(
OpenStudy (anonymous):
I guess u mean not factorisable, it is of course, divisible, just with a remainder.
However, considering the level of the question, I agree it is very likely a mistake in the question.