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Square root of 8y^3z^2
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2yz@2y
or 2yz√2y
\[\sqrt{8y ^{3}z ^{2}} = \sqrt{2*4*y*y*y*z*z} = 2yz \sqrt{2y}\]
\[\sqrt[5]{32x ^{8}y ^{3}z ^{2}5}\]
can some one give me step by spet instructions or explain how to solve this i honestly have no idea
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