Question

Answer this for me? <3
A 48 gram sample of a substance that's used for drug research hak-value of 0.1325.
N=n0e^-kt
N0= initial mass
N= mass at time t
K= a positice constant that depends on the substance itself and on the units used to measure time
t= time, in days

Find the substance's half-life, in days.
Round answer to the nearest tenth

Answer 1

answer it for you?

Answer 2

Please?

Answer 3

what part of it is giving you troubles?

Answer 4

if i recall correctly, the time taken to scale it has nothing to do any amounts.

ln(scalar)/rate = time

Answer 5

and the scalar here is 1/2, but id have to dbl chk meself

Answer 6

N/2 = N e^-kt

1/2 = e^-kt

ln(1/2) = -kt

ln(1/2)/-k = t

Answer 7

as i has it it would have just popped out a negative time; to which you can ignore the sign

Answer 8

all we have to do is plug this into a calculator to find the answer:

-ln(1/2)/.1325 = t

Answer 9

google gives us this:

http://www.google.com/search?sourceid=chrome&ie=UTF-8&q=-ln(1%2F2)%2F.1325

Answer 10

:O , your good !