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Determine a region whose area is equal to the given limit. Do not evaluate the limit. lim┬(n→∞)∑_(i=1 )^n 2/n (1+2i/n)^18
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can you possibly use the equation thing on the bottom to write this out?
\[\lim_{n \rightarrow \infty} \sum_{i=1}^{n} \left( 1+ 2i/n\right)^{18}\]
I know that the interval [a,b] is [1,3] because \[x _{i}=a+i \Lambda x=1+2i/n\]
I just don't know how to find the region from this information
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