Question

Square root of 3d^2-8= d-2

Answer 1

\[\sqrt{3d^2-8}=d-2\]

Answer 2

square it
3d^2-8=d^2-4d+4....

Answer 3

2d^2+4d-12=0

Answer 4

d^2+2d-6=0

Answer 5

My options are 3/4 , 3/-4 , 3 , 4 .

Answer 6

is none of thse a option?

Answer 7

N0 .

Answer 8

wait a min

Answer 9

i believe the question is wrong you will get the answer in root

Answer 10

plz comfirm the question... if it is it then i must say it is wrong.. sorry:(

Answer 11

what is this?

Answer 12

have i done a mistake?????? its not matching :(

Answer 13

no solution to this one

Answer 14

ok so d ques is wrong... i was worried..sorry guys.. phew

Answer 15

the line
\[y=x-2\] lives below the curve
\[y=\sqrt{3x^2-8}\]

Answer 16

I got it . The answer is 3/4 .

Answer 17

Lyssah621how??????????

Answer 18

oh no it is not

Answer 19

3/4 is not in the domain of
\[\sqrt{3x^2-8}\]