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find y such that the distance between the points is 8. (5,1) and (5,y)
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1+8 = ?
or 1-8 as well
\[8=\sqrt{(5-5)^2+(1-y)^2}\] \[8=1-y\] \[8-1=-y\] y=-7
or -8=1-y -8-1=-y y=9
distance formula for measuring on vertical line; cute :)
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oh lol thx
x coordinates are same so this is a "vertical" line through x = 5.
lol
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