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Multiplication of radicals find the value of (I will post it in equation form below)
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\[\sqrt{2/3} × \sqrt{4/5} \times \sqrt{3/4}\]
\[\sqrt{2/3} * \sqrt{4/5}* \sqrt{3/4}\] is the same as\[\sqrt{2/3 * 4/5 * 3/4}\] so we can solve this as we would normal fractions to give us \[\sqrt{2/5}\]
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