Question

Find the minimum value of the quadratic function below, correct to two decimal places. Please show work.

f(x)=x^2+2.85x+5.87

Answer 1

at x=-1.425

Answer 2

how did you get that?

Answer 3

The minimum value is just the y-coordinate of the vertex.
use the same process as before
x = -b/2a
Then substitute that value back into equation to get y-coordinate

Answer 4

Oh ok thanks