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find the derivative of x+5/x+2, instead of -3/x+2^2, i got 3/x+2^2
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\[(\frac{x+5}{x+2})'=\frac{(x+5)'(x+2)-(x+2)'(x+5)}{(x+2)^2}\]
\[=\frac{(1+0)(x+2)-(1+0)(x+5)}{(x+2)^2}\] \[=\frac{x+2-(x+5)}{(x+2)^2}\]
\[=\frac{-3}{(x+2)^2}\]
thanks! quick question. in any other problem like this, do you always sub in 1?
derivative of x is 1 i didn't sub in 1 thats just what the derivative of x is
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