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Mathematics 19 Online
OpenStudy (anonymous):

solve the inequality lx-1l<1

OpenStudy (anonymous):

lx-1l<1 x-1<-1 , x-1<1 x<0 , x<2

OpenStudy (anonymous):

-1<x-1<1 0<x<2

myininaya (myininaya):

ishaan is right

OpenStudy (anonymous):

It follows the Rule if |a|<b then -b<a<b

OpenStudy (anonymous):

Reeses do you want to know how it happen this way ?

OpenStudy (anonymous):

yes please

OpenStudy (saifoo.khan):

ISHAAAN!

OpenStudy (anonymous):

well | a| any quantity inside mod will give only positive outcome so if |a| < b it is extremely necessary that -b<a<b lets put a = -b |-b|<b -(-b)<b b<b well you see that it ain't possible how could 1 be less then 1

OpenStudy (anonymous):

SAIFOO !!!

OpenStudy (anonymous):

alrighty thanks!!!!!!!!! this helps a lot!

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