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solve the inequality lx-1l<1
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lx-1l<1 x-1<-1 , x-1<1 x<0 , x<2
-1<x-1<1 0<x<2
ishaan is right
It follows the Rule if |a|<b then -b<a<b
Reeses do you want to know how it happen this way ?
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yes please
ISHAAAN!
well | a| any quantity inside mod will give only positive outcome so if |a| < b it is extremely necessary that -b<a<b lets put a = -b |-b|<b -(-b)<b b<b well you see that it ain't possible how could 1 be less then 1
SAIFOO !!!
alrighty thanks!!!!!!!!! this helps a lot!
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