Question

find the zeros and axis of symmentry for y=x^2+x-12

Answer 1

zeros: D=7^2
x1 =-4
x2 =3

Answer 2

http://www.wolframalpha.com/input/?i=y%3Dx^2%2Bx-12

Click properties.

Answer 3

for axis of symmetry use
\[x=\frac{-b}{2a}\] in this case
\[x=-\frac{1}{2}\]

Answer 4

Ok. ThankYouu