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Mathematics 21 Online
OpenStudy (tabby):

√132-x=x

OpenStudy (anonymous):

aaaa

OpenStudy (akshay_budhkar):

u scared the person estudier lol!!!! what was that?

OpenStudy (anonymous):

method is square both sides to get \[132-x=x^2\] then solve \[x^2+x-132=0\] \[(x-11)(x+12)=0\] \[x=11\] or \[x=-12\] and then reject the solution x = -12 because it does not satisfy original equation

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