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An open rectangular box is to be constructed from a piece of cardboard a=25cm by b=46cm, by cutting squares of length x from each corner and folding up the sides. What should by equation be for this?
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*my, not by
i bet this really means "what is the equation for the volume ?" yes?
Yes
should be \[V(x)=x(25-2x)(46-2x)\]
Then what should I do?
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if you draw a picture it will be clear. now we want to maximize volume i bet \[v(x)=4 x^3-142 x^2+1150 x\] \[V'(z)= 2 (6 x^2-142 x+575)\] set equal zero and solve, get \[x= \frac{71-\sqrt{1591}}{6}\]
you did not ask that question but i am guessing that it is what the question is after
wait, I don't understand why it isn't V(z)=2(2x^3-71x^2+575x)
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