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Graph the linear inequality: x-y>3
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Yes, I did. But I can't understand the way it was graphed.
Okay what is the equation your using to graph? Rem you have to set it to y> in order to graph
=x-y>3 =-y>3+x =y>(3+x)/(-1) Plug in positive and neg values for x. So by hand construct a table using -5, -2, 0, 2, 5 any x-values that are whole numbers
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Or use a graphing calc
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