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OpenStudy (anonymous):
Seperate 72 into two parts, one of which shall be 1/3 of the other
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OpenStudy (anonymous):
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OpenStudy (anonymous):
\[ x+y = 72\] \[y = \frac{1}{3}x\]
OpenStudy (anonymous):
\[\frac{4x}{3} = 72\]
OpenStudy (anonymous):
\[Now \:\:Solve\:\:\]
OpenStudy (anonymous):
The solving part is what I am confused about!!!
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OpenStudy (anonymous):
x= 54, 1/3X=18 so 54 and 18
OpenStudy (anonymous):
Thanks
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